Subset Sum(dpss)

github

This is a Rust implementation that calculates subset sum problem using dynamic programming. It solves subset sum problem and returns a set of decomposed integers. It also can match corresponding numbers from two vectors and be used for Account reconciliation.

Any feedback is welcome!

There are four ways to use this program. * CLI🖥️ * Rust🦀 * Python🐍 * Web🌎 (Easy to use)

Here is also an out of the box example of python you can run now in google colab. https://colab.research.google.com/github/europeanplaice/subsetsum/blob/main/python/pythonsubset_sum.ipynb

And it has two methods.

find_subset
- It finds a subset from an array.
Sequence Matcher
- It finds subset sum relationships with two arrays. Solving multiple subset sub problem.

dpss is short for dynamic programming subset sum.

Links

CLI

Installation

Binary files are provided on the Releases page. When you download one of these, please add it to your PATH manually.

Usage

Subset sum

First, you need to prepare a text file containing a set of integers like this 1 2 -3 4 5 and save it at any place.

Second, call subset_sum with the path of the text file and the target sum.

Example

Call subset_sum.exe num_set.txt 3 3
The executable's name subset_sum.exe would be different from your choice. Change this example along with your environment. The second argument is the target sum. The third argument is the maximum length of the combination.

In this example, the output is
[[2, 1], [4, -3, 2], [5, -3, 1]]

Sequence Matcher

arr1.txt 1980 2980 3500 4000 1050

arr2.txt 1950 2900 30 80 3300 200 3980 1050 20

Call subset_sum.exe arr1.txt arr2.txt 100 100 10

In this example, the output is
``` pattern 1 => [((1050) -> [1050] == [1050]) ((12460) -> [1980 + 2980 + 3500 + 4000] == [20 + 30 + 80 + 200 + 1950 + 2900 + 3300 + 3980])],

pattern 2 => [((13510) -> [1050 + 1980 + 2980 + 3500 + 4000] == [20 + 30 + 80 + 200 + 1050 + 1950 + 2900 + 3300 + 3980])],

pattern 3 => [((1980) -> [1980] == [30 + 1950]) ((11530) -> [1050 + 2980 + 3500 + 4000] == [20 + 80 + 200 + 1050 + 2900 + 3300 + 3980])],

pattern 4 => [((2980) -> [2980] == [80 + 2900]) ((10530) -> [1050 + 1980 + 3500 + 4000] == [20 + 30 + 200 + 1050 + 1950 + 3300 + 3980])],

pattern 5 => [((2980) -> [2980] == [80 + 2900]) ((4000) -> [4000] == [20 + 3980]) ((6530) -> [1050 + 1980 + 3500] == [30 + 200 + 1050 + 1950 + 3300])],

pattern 6 => [((6980) -> [2980 + 4000] == [20 + 80 + 2900 + 3980]) ((6530) -> [1050 + 1980 + 3500] == [30 + 200 + 1050 + 1950 + 3300])],

pattern 7 => [((3500) -> [3500] == [200 + 3300]) ((10010) -> [1050 + 1980 + 2980 + 4000] == [20 + 30 + 80 + 1050 + 1950 + 2900 + 3980])],

pattern 8 => [((7500) -> [3500 + 4000] == [20 + 30 + 200 + 1050 + 2900 + 3300]) ((6010) -> [1050 + 1980 + 2980] == [80 + 1950 + 3980])],

pattern 9 => [((4000) -> [4000] == [20 + 30 + 1050 + 2900]) ((9510) -> [1050 + 1980 + 2980 + 3500] == [80 + 200 + 1950 + 3300 + 3980])],

pattern 10 => [((4000) -> [4000] == [20 + 3980]) ((9510) -> [1050 + 1980 + 2980 + 3500] == [30 + 80 + 200 + 1050 + 1950 + 2900 + 3300])], ```

Use in Python

installation

pip install dpss

Usage

`find_subset`

python import inspect import dpss help(dpss.find_subset) ```

findsubset(arr, value, maxlength, /) Finds subsets sum of a target value. It can accept negative values. # Arguments * arr - An array. * value - The value to the sum of the subset comes. * max_length - The maximum length of combinations of the answer. ```

python print(dpss.find_subset([1, -2, 3, 4, 5], 2, 3)) ```

[[4, -2], [3, -2, 1]] ```

`sequence_matcher`

python help(dpss.sequence_matcher) ```

sequencematcher(keys, targets, maxkeylength, maxtargetlength /) Finds the integers from two vectors that sum to the same value. This method assumes that the two vectors have Many-to-Many relationships. Each integer of the keys vector corresponds to the multiple integers of the targets vector. With this method, we can find some combinations of the integers. # Arguments * keys - An array. * targets - An array. * max_key_length - An integer. * max_target_length - An integer. * n_candidates - An integer. python a = dpss.sequencematcher( [1980, 2980, 3500, 4000, 1050], [1950, 2900, 30, 80, 3300, 200, 3980, 1050, 20], 10, 10, 10) print(dpss.sequencematcherformatter(a)) pattern 1 => [((1050) -> [1050] == [1050]) ((12460) -> [1980 + 2980 + 3500 + 4000] == [20 + 30 + 80 + 200 + 1950 + 2900 + 3300 + 3980])],