nom-recursive

Extension of nom to handle left recursion.

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Requirement

nom must be 5.0.0 or later. nom-recursive can be applied to function-style parser only.

The input type of nom parser must implement HasRecursiveInfo trait. Therefore &str and &[u8] can't be used. You can define a wrapper type of &str or &[u8] and implement HasRecursiveInfo.

Alternatively you can use nom_locate::LocatedSpan<T, RecursiveInfo>. This implements HasRecursiveInfo in this crate.

Usage

Cargo.toml [dependencies] nom-recursive = "0.5.0"

Example

```rust use nom::branch::; use nom::character::complete::; use nom::IResult; use nomlocate::LocatedSpan; use nomrecursive::{recursive_parser, RecursiveInfo};

// Input type must implement trait HasRecursiveInfo // nom_locate::LocatedSpan implements it. type Span<'a> = LocatedSpan<&'a str, RecursiveInfo>;

pub fn expr(s: Span) -> IResult { alt((expr_binary, term))(s) }

// Apply recursive_parser by custom attribute

[recursive_parser]

pub fn expr_binary(s: Span) -> IResult { let (s, x) = expr(s)?; let (s, y) = char('+')(s)?; let (s, z) = expr(s)?; let ret = format!("{}{}{}", x, y, z); Ok((s, ret)) }

pub fn term(s: Span) -> IResult { let (s, x) = char('1')(s)?; Ok((s, x.to_string())) }

fn main() { let ret = expr(LocatedSpan::new_extra("1+1", RecursiveInfo::new())); println!("{:?}", ret.unwrap().1); } ```

License

Licensed under either of

at your option.

Contribution

Unless you explicitly state otherwise, any contribution intentionally submitted for inclusion in the work by you, as defined in the Apache-2.0 license, shall be dual licensed as above, without any additional terms or conditions.