ConcatSQL

ConcatSQL(concatsql) is a secure SQL database library.
You can use string concatenation to prevent SQL injection.

Documentation

Supported databases: - PostgreSQL - MySQL - SQLite

You can configure the database backend in Cargo.toml:

toml [dependencies] concatsql = { version = "<version>", features = ["<postgres|mysql|sqlite>"] }

Examples

Normal value

```rust let id = String::from("42"); // User supplied input let passwd = String::from("pass"); // User supplied input

let sql = prep!("SELECT name FROM users WHERE id=") + &id + prep!(" AND passwd=") + &passwd; assert_eq!(sql.simulate(), "SELECT name FROM users WHERE id='42' AND passwd='pass'");

for row in conn.rows(&sql).unwrap() { asserteq!(row.get(0).unwrap(), "Alice"); asserteq!(row.get("name").unwrap(), "Alice"); } ```

Illegal value

```rust let id = String::from("42"); // User supplied input let passwd = String::from("'' or 1=1; --"); // User supplied input

let sql = prep!("SELECT name FROM users WHERE id=") + &id + prep!(" AND passwd=") + &passwd; assert_eq!(sql.simulate(), "SELECT name FROM users WHERE id='42' AND passwd=''''' or 1=1; --'");

for row in conn.rows(&sql).unwrap() { unreachable!(); } ```

If you did not use the prep macro

Cannot compile ... secure!

rust let id = String::from("42"); let passwd = String::from("' or 1=1; --"); let sql = "SELECT name FROM users WHERE id=".to_string() + &id + " AND passwd='" + &passwd + "';"; conn.execute(&sql).unwrap(); // error

When using prep!(<String>)

Cannot compile ... secure!

rust let age = String::from("50 or 1=1; --"); let sql = prep!("SELECT name FROM users WHERE age < ") + prep!(&age); // error

Why can this library prevent SQL injection?

This is because it is achieved using Operator Overloading rather than simple string concatenation.
The prep macro returns the library's own type(WrapString).
For example, if you combine this WrapString type with a String type, the escaped String type will be combined and a new WrapString will be returned.

rust let foobar: WrapString = prep!("foo") + String::from("bar");

Is it impossible to implement in other languages?

It seems that it can be implemented in other languages as long as it supports operator overloading.
However, if the developer writes the following, the input from the attacker will not be escaped correctly and the attack will be successful.

python prep("SELECT * FROM users WHERE id=" + id + " AND PASSWORD=" + password)

That is, it can be implemented in any language that can distinguish between hard-coding(&'static str) and user input(String) at compile time.

License

MIT